How High Does a Ball Go When Thrown Upward at 25m/s?

AI Thread Summary
To determine how high a ball thrown upward at 25 m/s will go, one must use kinematic equations, particularly considering gravity as a negative acceleration of -9.81 m/s². The initial velocity (v₀) is 25 m/s, and the final velocity (v) at the peak height will be 0 m/s. By applying the equation v² = v₀² + 2aS, where 'a' is the acceleration due to gravity, the maximum height can be calculated. The time to reach this height can also be found using the equation T = (v - v₀) / a. Understanding these principles is essential for solving the problem accurately.
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Homework Statement


A ball is thrown stright up with the speed 25m/s
how high does the ball go?

Homework Equations


S=v*t or V=vot+at
I know gravity is a neg acceloration so I should have -9.81 somewhere



The Attempt at a Solution


I need to find the time first am guessing so, T=s/v but i don't know S ether just 25m/s and -9.81 I know this is most likly very simple but it just eludes me
 
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