How is (1/2)V_id expressed in this circuit?

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Discussion Overview

The discussion revolves around the configuration of a circuit in LTSpice, specifically focusing on how to express (1/2)V_id in the context of voltage-controlled voltage sources (VCVS). Participants explore the implications of common mode voltage (Vcm) and differential input voltage (Vid) within the circuit design.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant notes the absence of Vin1 and Vin2 in the provided diagram and suggests that they correspond to the "+" nodes of the op-amps.
  • Another participant questions the expression of Vin as ##V_{CM}/2 + V_{ID}/2##, indicating it may not apply to the circuit in question.
  • There is a suggestion that the diamonds in the diagram represent controlled voltage sources rather than current sources, which leads to a discussion about their configuration.
  • A participant proposes creating two additional voltage sources of ##V_{ID}## and using VCVSs with a gain of 0.5 to achieve the desired configuration in LTSpice.
  • Another participant emphasizes the effect of common mode voltage on both op-amps and the advantage of using two VCVSs to simplify the input voltage control.

Areas of Agreement / Disagreement

Participants express differing views on the configuration of the circuit and the interpretation of the voltage sources. There is no consensus on how to express (1/2)V_id or the correct approach to configuring the circuit in LTSpice.

Contextual Notes

Participants highlight potential misunderstandings regarding the circuit diagram and the roles of various components, particularly the voltage sources and their relationships to the op-amps. The discussion remains open regarding the correct configuration and assumptions about the circuit's behavior.

song youngill
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Homework Statement
instrumentation amplifier in ltspice
Relevant Equations
vin=1/2(vid)+1/2(vcm)
df.jpg

As you can see in the picture, 1/2vid is entered in each of Vin1 and Vin2 on the left. Assuming Vcm is 0, I need to configure this circuit with ltspice, but I am not sure how to configure this vcvs. I'd appreciate it if you could tell me how.
 
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Your diagram does not show any Vin - neither Vin1 nor Vin2.
That said, I would guess that Vin1 and Vin2 are the "+" nodes of the top and bottom op amps, respectively.
If that is the case, then neither Vin is ##V_{CM}/2 + V_{ID}/2##.

One other thing. Those diamonds are most commonly a symbol for a current source. But they are labelled with a voltage value (##(1/2) V_{ID}##). So I take them as controlled voltage sources.
 
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.Scott said:
Your diagram does not show any Vin - neither Vin1 nor Vin2.
That said, I would guess thaVin1 and Vin2 are the "+" nodes of the top and bottom op amps, respectively.
If that is the case, then neither Vin is ##V_{CM}/2 + V_{ID}/2##.
sorry. vin1 is upper amp's + input and vin2 is lower amp's + input. The does 1/2vid can't be configured as vcvs in ltspice?
 
song youngill said:
sorry. vin1 is upper amp's + input and vin2 is lower amp's + input. The does 1/2vid can't be configured as vcvs in ltspice?
Oh, I see. Those diamonds are supposed to be Voltage Controlled Voltage Sources (VCVS's).
I am not familiar with ltspice. Perhaps you would need to actually draw out the voltage divider.
But do you realize that the value you specified before, ##V_{CM}/2 + V_{ID}/2##, is not a voltage level used in this circuit?
 
OK. I just checked out LTSpice.
It looks like you need to create two more voltage sources - each ##V_{ID}##. Then use those with "e" components (VCVSs), each with a gain value of 0.5.
That should do the trick.
 
.Scott said:
OK. I just checked out LTSpice.
It looks like you need to create two more voltage sources - each ##V_{ID}##. Then use those with "e" components (VCVSs), each with a gain value of 0.5.
That should do the trick.
You can probably replace it with an equivalent independent voltage source. I need to observe the vo value according to the change of the vid, so I hope I can solve the vid.
 
Here is a bit more detail.

VID is Voltage, Input, Differential (or differential input voltage)

The simulation circuit shows that the VCM (Common Mode Voltage) affects both input OpAmps.

Tha advantage of using the two VCVS's is you need to vary only one input voltage (independent voltage source) which then controls the two VCVS's and both differential inputs to the circuit.

Have Fun!

Cheers,
Tom
 

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