Engineering How is Current Determined in a Single Phase AC Circuit with a Moving Conductor?

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In a single-phase AC circuit with a moving conductor, the current can be determined using Faraday's law of electromagnetic induction. For the given problem, when the conductor is open-circuited, no current flows, while connecting it to a 20-ohm load allows calculation of the induced current using Ohm's law. The induced electromotive force (e.m.f.) can be calculated using the formula e.m.f. = B * L * v, where B is the magnetic flux density, L is the length of the conductor, and v is its velocity. For the second question, the induced e.m.f. in a coil can be found using the formula e.m.f. = -L * (di/dt), where L is the inductance and di/dt is the rate of change of current. Understanding these principles is crucial for solving the problems effectively.
ric115
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Hi there

Im new to this site and i have noticed that you give advice to electronic questions. Presently I am studing electronics and on some of my course work i am having some difficulty in understanding some of the questions. such as,

Q1
A conductor 300mm long moves at a uniform speed of 4m/s at right-angles to a uniform magnetic field of flux density 1.25T. Determine the current flowing in the conductor when:

a) its end are open-circuited

b) its ends are connected to a load of 20 ohm resistance

and,

Q2
Calculate the e.m.f induced in a coil of inductance 12 H by a current changing at the rate of 4 A/s

Any advice or helpfull sites to visit would be much appreciated,

Thanking you in advance

Rich
 
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Welcome to Physics Forums.

Since you didn't post your questions in the homework section, you're unaware of our policy on this type of question (not your fault).

Can you provide:

A. any equations from your class lectures or textbook that appear to be relevant to solving the problems, and

B. provide your thoughts or attempt at solving the problems (doesn't have to lead to a final solution)
 

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