How Is Electric Flux Calculated Through a Tilted Surface?

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Electric flux through a tilted surface can be calculated using the formula flux = EAcos(theta). In this case, the electric field magnitude is 2000 N/C, and the area of the square surface is 1.444 x 10^-5 m². The angle used in the calculation is 145°, derived from the 35° angle between the electric field lines and the normal to the surface. The resulting electric flux is approximately -0.023657 N*m²/C, indicating the direction of the flux is opposite to the outward normal. This calculation confirms the correct application of the electric flux formula.
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[SOLVED] Flux through a surface

Homework Statement


The square surface shown in Figure 24-26 measures 3.8 mm on each side. It is immersed in a uniform electric field with magnitude |E| = 2000 N/C. The field lines make an angle of 35° with a normal to the surface, as shown. Take that normal to be directed "outward," as though the surface were one face of a box. Calculate the electric flux through the surface.

http://personalpages.tds.net/~locowise/test/24-26.gif

E=2000N/C
theta=(180-35)=145
A=(0.0038m)^2=1.444*10^-5 m^2


Homework Equations


flux=EAcos(theta)



The Attempt at a Solution


flux=2000N/C * (1.444*10^-5 m^2) cos145 = -0.023657 N*m^2/C
 
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Your answer is correct, and your work looks sound. Do you have any other questions?
 

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