How Is EMF Induced in a Loop Within a Solenoid?

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AI Thread Summary
The discussion revolves around calculating the induced electromotive force (emf) in a small loop placed within a solenoid with a sinusoidally varying current. The loop has an area of 6.8 mm², and the solenoid has 854 turns/cm with a current amplitude of 1.28 A and an angular frequency of 212 rad/s. The initial calculations suggest an induced emf of 6.29E-5 V, but the expected answer is 0.198 mV. Participants clarify that the correct approach involves using the derivative of the current with respect to time, leading to agreement on the 0.198 mV result. The discussion emphasizes the importance of accurately applying the equations for magnetic flux and induced emf.
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Homework Statement


A small loop with area 6.8 mm^2 is placed in a long solenoid with 854 turns/cm and a sinusoidally varying current w/ amplitude 1.28 A and angular frequency of 212 rad/s. What is the amplitude of the emf induced in the loop?

Homework Equations


\textbf{B}=\mu_0 in
\Phi_B = BA
emf = \frac{d\Phi_B}{dt}

The Attempt at a Solution


Since the current is changing, the emf through the loop should be \mu_0 n A \frac{di}{dt}
If the angular frequency is 212 rad/s, then the current changes by 1.28 A in half a period, which is \frac{\pi}{212} seconds. So the induced emf should be 6.29E-5 V, but the answer is .198 mV.
 
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kinof said:
1.

If the angular frequency is 212 rad/s, then the current changes by 1.28 A in half a period, which is \frac{\pi}{212} seconds. So the induced emf should be 6.29E-5 V, but the answer is .198 mV.

Does not make sense to me.

If the current is i*sin(wt), what is di/dt? The rest of what you did looks OK.

BTW I also get 0.198 mV.
 
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