How Is Induced Current Calculated in a Rectangular Loop?

AI Thread Summary
The discussion revolves around calculating the induced current in a rectangular loop with a resistance of 20.0 mΩ, resulting in an answer of 66.7 µA. Participants express confusion about applying the relevant equations, particularly Faraday's law of induction and the Biot-Savart law, to determine the changing magnetic flux through the loop. There is a debate on the appropriate radius to use for calculations, whether it should be the inner or outer side of the loop. Integration over the loop radius is suggested as necessary for accurate flux calculation. The conversation highlights the challenges faced by students in understanding these concepts and the need for clear guidance on the application of the laws involved.
erinec
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Homework Statement


The rectangular loop shown has resistance 20.0 mΩ.
Determine the induced current in the loop at the instant shown.
Answer: 66.7µA
http://img264.imageshack.us/img264/7386/picture1nlz.png


Homework Equations



induced emf = |d(flux)/dt|
I = emf / R

The Attempt at a Solution


I am so lost as to what to do... and I am so desperate.. If you could tell me the steps to solve this question, i would appreciate it very much.
 
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Show us the Biot-Savart Law (that gives you the B(r) around the wire). Then show us the rest of the solution. I have to give myself an infraction now for giving too big of a hint...
 
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Well... the problem is that.. I got this far:

emf = | d(flux)/dt |
= dB * A / dt
= dB (0.04*0.01) / dt
= dB (4*10^-4) / dt

but i do not know how to get dB...;
in other words, i am totally lost.I have B(r) = u0I/(2*pi*r)

This is my first time seeing this type of question.. and I am very confused as to what I'm doing.

Sorry if it sounds stupid.
 
The loop is moving with respect to the wire. So the B(t) through the loop will be changing, since the B is weaker the farther you get away from the wire. Write an equation based on the Biot-Savart Law for the flux throught the loop as a function of radius, and work from there...
 
Which radius should I use? The distance from the wire to the the inner side of the loop or the outer side of the loop?
 
erinec said:
Which radius should I use? The distance from the wire to the the inner side of the loop or the outer side of the loop?

You need to integrate over the loop radius.
 
I know this is old but I'm working on the exact same question.

So far i have this:
[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21%5Cphi%20%3D%20B%20%5Cbullet%20dA%20%5C%5CB%20%3D%20%5Cmu_0%20I/%20%282%20%5Cpi%20r%29%20%5Ctextrm%7B%20by%20ampere%27s%20law%7D%20%5C%5C%5Cphi%20%3D%20%5Cmu_0%20I/%20%282%20%5Cpi%20r%29%5Cbullet%20dA%20%5C%5C%5Cphi%20%3D%20%5Cmu_0%20I/%20%282%20%5Cpi%20r%29%20L%20dr%20%5C%5C%5Cphi%20%3D%20%5Cint_a%5Eb%20%5Cmu_0%20I/%20%282%20%5Cpi%20r%29%20L%20dr%20%5C%5C%5Cphi%20%3D%20%5Cfrac%7B%20%5Cmu_0%20I%20%5Cln%7B3/2%7D%7D%7B%5Cpi%7D.gif


Where the bounds of integration are b = 0.02 and a = 0.03 and L= 4.0cm from the picture. This is where i get lost. I wanted to use faraday's law to use:

[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21%5Ceps%20%3D%20%5Cmid%20%5Cfrac%7Bd%20%5Cphi%7D%7Bdt%7D%20%5Cmid.gif

Am i just totally going about this the wrong way by trying to use flux, and i have to use biot savart law?
 

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