How Is the Average Force Calculated When a Pile Driver Hits a Beam?

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Homework Help Overview

The problem involves a 2100 kg pile driver that impacts a steel I-beam after falling 5 m and drives it 12 cm into the ground. The objective is to calculate the average force exerted by the beam on the pile driver using energy considerations.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of angles in the work-energy principle, specifically questioning the application of cos 0 and cos 180 in the context of work done by forces. They explore the relationship between force, displacement, and the angles involved.

Discussion Status

Some participants have provided explanations regarding the angles and the definition of work, while others are seeking clarification on the specific angles used in the calculations and the reasoning behind the different displacements considered for gravity and the beam force.

Contextual Notes

Participants are examining the definitions and implications of work in the context of forces acting during the pile driver's motion, noting the difference in displacement for gravitational work versus the work done by the beam.

-EquinoX-
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Homework Statement


A 2100 kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 5 m before coming into contact with the top of the beam. Then it driver the beam 12 cm farther into the ground as it comes to rest. Using energy considerations, calculate the average force the beam exerts on the pile driver while the pile driver is brought to rest.


Homework Equations





The Attempt at a Solution



http://img238.imageshack.us/img238/7935/beamdi0.jpg
http://g.imageshack.us/img238/beamdi0.jpg/1/

I don't understand why they use cos 0 and cos 180 here? Can someone please explain it to me?
 
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You use the cos of 0 and 180 because that is the angle between the Force and displacment. This is the definition of Work. W=Fdcos(angle). This would make the work either negative or positive. If one moves an object against a force(gravity) then there would be a negative Wnet. If one moves an object with a force(gravity) the positive work is being done. Again, This is all due to the definition of work W=fdcos(angle)
 
okay, I get all that, however I can't see that that angle between the force and displacement is 0 and 180, can you please show me that? also why is it on the Wgravity the displacement is h+d and on the beam it's only d?
 
-EquinoX- said:
okay, I get all that, however I can't see that that angle between the force and displacement is 0 and 180, can you please show me that?
Compare the direction of the displacement (down) with the direction of gravity and the direction of the force from the beam.
also why is it on the Wgravity the displacement is h+d and on the beam it's only d?
The beam force only acts while in contact with the pile driver, which is over the distance d. Gravity acts on the pile driver during its fall as well (thus h+d).
 
the direction of the displacement and the gravity are both down.. so is that why it's 0?
 
-EquinoX- said:
the direction of the displacement and the gravity are both down.. so is that why it's 0?
Yes. They are two vectors that point in the same direction, so the angle between them is 0.
 

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