How is the Minimum Value of a Multivariable Function Determined in a Quadrant?

MeMoses
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Homework Statement


f(x,y) = x^3 - 3x^2 - 6xy + 7y + y^2, x>=0, y>=0
i) Explain why f attains its minimum value on the quadrant.
ii) Find the critical points and classify them


Homework Equations


df/dx = 3x^2 - 6x -6y
df/dy = -6x + 7 +2y

d^2f/dx^2 = 6x-6
d^2f/dy^2 = 2
d^2f/(dxdy) = -6

The Attempt at a Solution


It's been awhile since I've done problems like this. Hopefully I am making some sense.
I'm not sure about i). Couldn't x=-infinity and y=-1 yield -infinity?
For ii) I get the critical points to be (7, 35/2) and (1, -1/2), but (1, -1/2) is not in the constraints. fxx is positive and the determinant of the Hessian at the first point is negative so it is a saddle point. If the constraints weren't there, how would I figure out the other point since fxx=0?
iii) I'm not sure the best way to go about this. Help would be appreciated.
Thanks
 
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MeMoses said:

Homework Statement


f(x,y) = x^3 - 3x^2 - 6xy + 7y + y^2, x>=0, y>=0
i) Explain why f attains its minimum value on the quadrant.
ii) Find the critical points and classify them


Homework Equations


df/dx = 3x^2 - 6x -6y
df/dy = -6x + 7 +2y

d^2f/dx^2 = 6x-6
d^2f/dy^2 = 2
d^2f/(dxdy) = -6

The Attempt at a Solution


It's been awhile since I've done problems like this. Hopefully I am making some sense.
I'm not sure about i). Couldn't x=-infinity and y=-1 yield -infinity?
For ii) I get the critical points to be (7, 35/2) and (1, -1/2), but (1, -1/2) is not in the constraints. fxx is positive and the determinant of the Hessian at the first point is negative so it is a saddle point. If the constraints weren't there, how would I figure out the other point since fxx=0?
iii) I'm not sure the best way to go about this. Help would be appreciated.
Thanks

If f(x,y) does attain a minimum in {x,y ≥ 0} it does so either at an interior point (i.e., a stationary point) or on the boundary ({x=0} or {y=0}). You can check f along the two boundary lines {x=0,y≥0} and {y=0,x≥0}. Then, the only remaining question is whether f is bounded from below in the first quadrant. If I were doing the question I would check whether f is bounded from below on the non-negative x and y axes, and if it is bounded from below for points of the form (x,k*x) with k > 0 and x ≥ 0.

RGV
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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