How Is the Sensitivity of a Ballistic Galvanometer Determined?

AI Thread Summary
The sensitivity of a ballistic galvanometer is calculated using the formula sensitivity = deflection/charge. In this case, a 3 microfarad capacitor charged at 2 volts results in a charge of 6 microcoulombs, leading to a sensitivity of 4 divisions per coulomb based on a deflection of 24 divisions. A question arises regarding the alternative perspective that sensitivity could be defined as charge/deflection, which would imply that a device with no deflection would have infinite sensitivity. This highlights a potential misunderstanding of the definition of sensitivity in this context. Ultimately, the established formula for sensitivity is confirmed as deflection per unit charge.
Amith2006
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Homework Statement


1) A capacitor of capacity 3 micro farad charged by a potential of 2 volt when discharged through a Ballistic galvanometer gives a deflection of 24 divisions. Determine the sensitivity of the Ballistic galvanometer.



Homework Equations





The Attempt at a Solution



The solution as given in my book is as follows:
Charge (Q) =Capacity x Potential difference
= 6 micro coulomb
Sensitivity= deflection/charge
= 24/6
= 4 division/coulomb
My question is: Isn’t sensitivity = charge/deflection?
 
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If you make it charge/deflection then a device which shows no deflection whatsoever no matter how high the charge has infinite sensitivity. :smile:
 
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