How Large is x(t) at Maximum Acceleration for an Oscillating Block?

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SUMMARY

The discussion centers on determining the displacement x(t) of an 18.0-kg block oscillating on a frictionless surface, described by the equation x(t) = (17.0 cm) cos[(22.0 rad/s) t + π rad]. It concludes that the magnitude of x(t) at maximum acceleration is 17.0 cm, as maximum acceleration occurs when the displacement is at its peak value. The participant initially struggled with the problem but realized that the amplitude provided in the equation directly indicates the maximum displacement.

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Homework Statement


A 18.0-kg block oscillates back and forth along a straight line on a frictionless horizontal surface. Its displacement from the origin is given by
x(t) = (17.0 cm) cos[( 22.0 rad/s) t + π rad]

What is the magnitude of x(t) when the block experiences its maximum acceleration?

Homework Equations


most are below

The Attempt at a Solution


i started to work backwords and solve for k but after that I am lost since i thought k is what i should be solving for

nm just realized it gave it to me in the problem you can delete this
 
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What is the magnitude of x(t) when the block experiences its maximum acceleration?
When the acceleration is maximum, x(t) is maximum i.e. a
 


ya the original eq had it as the very first term it was 17cm
 

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