How Long Does It Take Astronaut Jane to Drift Back to Her Spaceship?

AI Thread Summary
Astronaut Jane is stranded 75.0 meters from her spaceship after her lifeline comes loose. She throws a 2.00 kg wrench at 20.0 m/s, which helps her calculate her final velocity using conservation of momentum. The final velocity of Jane and her spacesuit is approximately -0.23 m/s. To determine the time it takes for her to drift back to the spaceship, the distance of 75.0 m must be divided by her speed of 0.229 m/s. This results in a clear method to find the time required for her return.
Mowgli
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Homework Statement



Astronaut Jane's lifeline to her spaceship comes loose and she finds herself stranded, "floating" 75.0m from the spaceship. She throws her 2.00kg wrench at 20.0m/s in a direction away from the ship. If she and her spacesuit have a combined mass of 175kg how long does it take her to coast back to the spaceship?



Homework Equations





The Attempt at a Solution



This one I am so lost about...

Do I use the equation: (Mass of Suit x Mass of Jane) Initial Velocity + Mass of wrench (Initial Velocity) = (M of Suit + M of Jane) (V 1 + M of wrench (V 1 of wrench)

Therefore = (175kg) 0 + 2kg (0) = (175kg) (final velocity + 2kg (20.0m/s)
 
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All is good to this point.
 
Do I have to factor in the fact that she floated 75 m away?
 
Mowgli said:
Do I have to factor in the fact that she floated 75 m away?

That does not influence conservation of momentum.

You only need the distance to find the time it takes to get back to the ship.
 
Mowgli said:

Homework Statement




Therefore = (175kg) 0 + 2kg (0) = (175kg) (final velocity + 2kg (20.0m/s)

then 0=175(final velocity) + 40

final velocity = -40/175
= -0.23 m/s ??
 
Mowgli said:
then 0=175(final velocity) + 40

final velocity = -40/175
= -0.23 m/s ??

Looks okay so far.
 
what else needs to be done?
 
Mowgli said:
what else needs to be done?
You need to find out how much time it takes for someone to travel 75.0 m when traveling at a speed of 0.229 m/s.
 
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