How Long Does It Take for a Capacitor to Reach 80% Charge in an RC Circuit?

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Homework Help Overview

The discussion revolves around determining the time it takes for a capacitor to reach 80% of its maximum charge in an RC circuit, specifically involving a 4.1e-6 F capacitor, a 36V battery, and an 851 ohm resistor. The original poster expresses uncertainty due to limited instruction on RC circuits.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to calculate the current and relates it to charge and time but struggles with the unknowns involved. Some participants suggest using the exponential charging equation for capacitors to find the maximum charge and time. Questions arise regarding the interpretation of maximum charge and the role of the changing current during the charging process.

Discussion Status

Participants are exploring the relationship between charge, time, and the capacitor's maximum charge. Guidance has been offered regarding the use of the exponential charging equation, and there is an ongoing clarification about the definitions and values needed to proceed with the calculations.

Contextual Notes

There is a noted lack of clarity regarding the maximum charge and the implications of the capacitor's charging behavior over time. The original poster indicates a gap in their understanding due to limited classroom instruction on the topic.

blackbyron
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Homework Statement



A 4.1e-6 capacitor is connected in series with a 36V battery and a 851 ohlms resistor. At t= 0 the capacitor is uncharged. At what time will the capacitor have 80% of its maximum charge?

Homework Equations


I = V/R
Q = CV
I = Q/t


The Attempt at a Solution


I didn't learn RC circuit much in class since my teacher ran out of time.
But anyway,

So the first thing I did is I found the current which is,

I = .0423 A

Now I'm stuck on this one.

I = Q/t I need to find t, I tried to use .0423 = Q* (.8) / t but the problem is Q is unknown. Any ideas?
 
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You're missing an important fact. The current will constant change as the capacitor charging, approaching zero. Is the 4.1e-6 supposed to be the farad value for it? You can use that in one of the equations you have to find the maximum Q. The equation you are missing is Q = Q_{max}[1 - e^{(-t/RC)}], I believe. Try getting the [1 - e^{(-t/RC)}] to get to the amount of the maximum charge you need.
 
MrNerd said:
You're missing an important fact. The current will constant change as the capacitor charging, approaching zero. Is the 4.1e-6 supposed to be the farad value for it? You can use that in one of the equations you have to find the maximum Q. The equation you are missing is Q = Q_{max}[1 - e^{(-t/RC)}], I believe. Try getting the [1 - e^{(-t/RC)}] to get to the amount of the maximum charge you need.
Thanks for your reply
But how do I find out out the max Q if q and t is unknown?
 
Last edited:
I think you misunderstood what I meant by max Q. The maximum Q is the highest charge the capacitor can hold with a given voltage. t is just the time, right? So you simply need to solve for t. I don't know if you already did this, but the inverse function of e is a natural log, shown as ln. So the natural log of e^x would give you x, and e^(lnx) would give you x as well. Remember, you want 80% of the maximum charge. The left q(the one by itself and equaling the other things) is the one you want at time t.
 
Solve for t as a function of R and C.
 

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