- #1
TR0JAN
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Here is the question:
Astronauts have connected a line between their 3280 kg space tug and a 6100 kg asteroid.
Using their ship's engine, they pull on the asteroid with a force of 490 N. Initially the tug and the asteroid are at rest, 490 m apart.
How much time does it take for the ship and the asteroid to meet?
-490N 490N
Tug(3280kg)-------><------Asteroid(6100kg)
490m
So Acceleration = Force/Mass
Acceleration for the asteroid is 490/6100 = .0803 m/s2
Acceleration for the tug is -490/3280 = -.149 m/s2
How do I calculate the time when given the initial speed, the distance between, and the acceleration of two objects?
Astronauts have connected a line between their 3280 kg space tug and a 6100 kg asteroid.
Using their ship's engine, they pull on the asteroid with a force of 490 N. Initially the tug and the asteroid are at rest, 490 m apart.
How much time does it take for the ship and the asteroid to meet?
-490N 490N
Tug(3280kg)-------><------Asteroid(6100kg)
490m
So Acceleration = Force/Mass
Acceleration for the asteroid is 490/6100 = .0803 m/s2
Acceleration for the tug is -490/3280 = -.149 m/s2
How do I calculate the time when given the initial speed, the distance between, and the acceleration of two objects?