How long does the box take to reach the wall?

  • Thread starter Thread starter radaballer
  • Start date Start date
  • Tags Tags
    Box Wall
AI Thread Summary
To determine how long it takes for a 10 g box pushed with a 20 Newton force to reach a wall 10 meters away, the coefficient of friction is crucial. Without this coefficient, the acceleration cannot be calculated, making it impossible to find the time. If the friction is negligible, one can assume zero friction, allowing for calculations based on the applied force alone. The initial velocity and acceleration can be derived from the known values if friction is disregarded. Ultimately, the problem requires clarification on the friction coefficient to solve accurately.
radaballer
Messages
86
Reaction score
0

Homework Statement


A stationary 10 g box is pushed with a force 20 Newtons across a level floor. How long will it take the box to reach a wall 10 meters away?

Homework Equations


Applied force - Friction Force?

The Attempt at a Solution


I am unsure how to attempt this. Do I need to know the static and moving coefficients of friction?
 
Last edited:
Physics news on Phys.org
I am unsure how to attempt this. Do I need to know the static and moving coefficients of friction?
... try it and see.

If you need the friction coefficients - are you given enough information to solve the problem?
 
  • Like
Likes radaballer
radaballer said:

Homework Statement


A stationary 10 g box is pushed with a force 20 Newtons across a level floor. How long will it take the box to reach a wall 10 meters away?

Homework Equations


Applied force - Friction Force?

The Attempt at a Solution


I am unsure how to attempt this. Do I need to know the static and moving coefficients of friction?
If you knew the kinetic coeff. of friction you could apportion part of the 20N force to overcoming friction and the rest (if any) to accelerating the box.

You could altenatively assume zero friction if that coeff. is not given to you.
 
From the problem you can tell what is the initial velocity and the acceleration, right?
 
jove8414 said:
From the problem you can tell what is the initial velocity and the acceleration, right?
Without the coefficient of friction, the acceleration is not knowable.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top