How Long Should a Rocket Fire to Adjust a Satellite's Speed?

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To adjust a satellite's speed, a rocket with a thrust of 35 N is used to change the velocity of a 72,000 kg spacecraft by 63 cm/s. The calculation involves using the impulse-momentum theorem, which states that impulse equals the change in momentum. The derived formula for time is Δt = mΔv/F, leading to a calculated firing time of 1296 seconds. The discussion highlights the importance of understanding impulse and its relation to momentum in solving the problem. The solution provided is confirmed as correct.
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Homework Statement



Small rockets are used to make small adjustments in the speed of satellites. One such rocket has a thrust of 35 N. If it is fired to change the velocity of a 72 000 kg spacecraft by 63 cm/s, how long should it be fired?


Homework Equations



Momentum = Mass x Velocity


The Attempt at a Solution



After reading the instructions, I'm still having difficulty on this particular problem.

There is a formala called pbefore = pafter

Where momentum in one object transfers to another when hit. But I just don't know where to begin.

Thanks.
 
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Hint: Consider the impulse delivered by the force. (Look it up!)
 
Thanks but I don't know what that has to do with my problem. Can you post an explanation of the formula or the solution?
 
What's the definition of impulse and what does it have to do with momentum? Look it up!
 
How am I supposed to calculate impulse with the information given?
 
What's the definition of impulse?
 
Iv'e gotten this solution:F = (mass x velocity) / time
35N = 72,000 x 0.63 / t
35N = 45,360 kg m/s / t
35t = 45,360kg m/s
T = 1296 seconds

Is it right?
 
pokeefer said:
Iv'e gotten this solution:


F = (mass x velocity) / time
35N = 72,000 x 0.63 / t
35N = 45,360 kg m/s / t
35t = 45,360kg m/s
T = 1296 seconds

Is it right?
Yes, very good.

Impulse = FΔt

And impulse equals the change in momentum, Δ(mv).

So:
FΔt = Δ(mv) = mΔv
Δt = mΔv/F
 
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