How many air molecules are there inside the tire?

AI Thread Summary
The discussion centers on calculating the number of air molecules in a car tire with a volume of 10 L and a gauge pressure of 30 psi at 20°C. The initial calculation used only the gauge pressure, resulting in 5.12 x 10^23 molecules. However, the correct approach requires adding atmospheric pressure to the gauge pressure to obtain absolute pressure, leading to the instructor's answer of 7.6 x 10^23 molecules. The key takeaway is that gauge pressure must be converted to absolute pressure for accurate calculations using the ideal gas law. Understanding this distinction is crucial for solving similar problems in physics.
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Homework Statement



A car tire has a volume of 10 L and is inflated to a gauge pressure of 30 psi (207,000 Pa) at 20°C. How many air molecules are there inside the tire?

Homework Equations


N = PV/ kbT

The Attempt at a Solution



(207,000 Pa )x (0.01 m3) / (1.38 x 10^-21 x 293) =5.12 x 10^23

However, my instructor's answer is:
( 101,000 + 207,000 Pa )x(0.01 m3) / (1.38 x 10-21 x 293) = 7.6 x 10^23

Where is he getting that extra 101,000 that he is adding to the pressure??
 
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SmugBug said:
Where is he getting that extra 101,000 that he is adding to the pressure??
Gauge pressure means the pressure that would be shown on a standard pressure gauge. That would be relative to ambient pressure. For the calculation you need absolute pressure, so atmospheric pressure must be added.
 
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30 psi is the gauge pressure. A gauge under atmospheric pressure reads zero.

Edit: oops haruspex said it first
 
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A gauge pressure of 30 psi means an absolute pressure of 30+14.7= 44-7 psi. The ideal gas law uses the absolute pressure, not the gauge pressure.
 
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