How Many Electrons Are Removed from a Charged Copper Ball?

AI Thread Summary
A 3.0mm-diameter copper ball charged to 50nC requires calculating the fraction of electrons removed. The density of copper is 8900kg/m^3, and the volume of the ball is calculated using the formula for the volume of a sphere. The user initially calculated the number of electrons in the ball as approximately 3.125 x 10^11 but encountered an error in their final answer of 5.682 x 10^-16. Clarification is sought on the calculations to identify where the mistake occurred. Accurate calculations are essential for determining the fraction of electrons removed from the charged copper ball.
Mek8388
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Homework Statement


A 3.0mm-diameter copper ball is charged to 50nC.What fraction of its electrons have been removed? The density of copper is 8900kgm^3.


Homework Equations



d=m/v; v=4/3* pi r^3

The Attempt at a Solution



I worked through it and got 5.682 E -16, but that answer was wrong. I first found the number of electrons were in it (3.125 E 11). I then found the volume (1.414 E -8), and I think that's where I got stuck after that.
 
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So what did you try to do after that?
 
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Mek8388 said:

The Attempt at a Solution



I worked through it and got 5.682 E -16, but that answer was wrong. I first found the number of electrons were in it (3.125 E 11). I then found the volume (1.414 E -8), and I think that's where I got stuck after that.
Can you show the work you did to get those numbers? It would be easier to help you if you do that.
 
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