How Many Elements Exist If n <= 4?

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If elements with a principal quantum number n greater than 4 were not allowed, the total number of possible elements is 60. The confusion arises from the misunderstanding of electron configurations and the filling order of orbitals. While the periodic table suggests a different count based on real atomic behavior, the question focuses solely on the theoretical limits of n. The formula 2n^2 indicates the maximum number of electrons per shell, but the actual filling sequence alters the expected results. Understanding these principles clarifies the discrepancy in the number of elements.
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Homework Statement


If elements with principal quantum number n > 4 were not allowed in nature, the number of possible elements would be
(A) 60
(B) 32
(C) 4
(D) 64

Homework Equations

The Attempt at a Solution


I got 36 from the periodic table (2+8+8+18)
However, that isn't even an option. The answer is 60. Please help.
 
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What are the rules that tell you how many electrons you can have for a given n?
 
2n^2
 
But looking from the periodic table, isn't my answer right?
 
erisedk said:
But looking from the periodic table, isn't my answer right?
If you take only elements which have at most ##n=4## electrons, you indeed get a different number, but this is not what the question is about. What you get from the periodic table depends on the fact that the energy ordering of orbitals doesn't depend only on n, which makes it such that 5s electrons are lower in energy than 4d electrons. But the question says that n is at most 4, so when the 4p orbitals are filled, you will fill the 4d orbitals (and not the 5s as is the case for real atoms). You end up with different electronic configurations.
 
Oh OK, so basically ignoring the energy order. Thank you!
 
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