How many oscillations until a damped block comes to rest?

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Homework Help Overview

The problem involves a block attached to a spring, which is subjected to damping forces due to friction. The objective is to determine how many oscillations the block undergoes before coming to rest.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss using conservation of energy to analyze the motion, questioning how it relates to the number of oscillations. Some suggest examining the energy changes at extreme positions to simplify the analysis.

Discussion Status

The discussion is ongoing, with various approaches being explored, including differential equations and energy conservation. Participants emphasize the importance of engaging with the problem and exploring different methods rather than seeking a straightforward solution.

Contextual Notes

Participants note the complexity of the problem and the learning process involved, highlighting that it is common to encounter difficulties and dead ends in problem-solving. There is also mention of specific values for mass, friction coefficient, amplitude, and spring constant, but no definitive conclusions are drawn.

VishalChauhan
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Homework Statement


A block of mass m is attached to a spring of spring constant k. It lies on a floor with coefficient of friction μ. The spring is stretched by a length a and released. Find how many oscillations it takes for the block to come to rest.

Homework Equations


d2x/dt2 + k/m x = +_ μg

Also the block will stop when the spring is unstretched and the velocity is 0

The Attempt at a Solution


I tried to write equations for each part of the motion (ie when the frition acts along and opposite to the spring force) but its too messy. Is there another than solving the differential equation for each part of the motion.
 
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conservation of energy?
look up the equation?
 
Simon Bridge said:
conservation of energy?
Thought so. But how would it give me the NUMBER of oscillations.
 
You can use conservation of energy to only look at the times when the block is in its extreme positions, so that you don't have to consider the change in kinetic energy. So, on any given swing, the change in stored elastic energy of the spring is equal to the work done against friction. This will tell you how much the amplitude decreases in any given swing.

Chet
 
Do you have the answer? If so can you please share it? I'd like to check my answer.

Try writing a sequence (if that's the correct term) for the amplitude after half-oscillations (if that makes sense).
 
The problem is usually given as an exercise in learning to solve problems in general.
That means that part of the learning process is going through the painful process of running into dead ends, trying other things out and so on.
There are several ways to approach the answer, you are supposed to discover one of them.

It is not as simple as getting a nice equation to plug numbers into - you do actually have to play around a bit to figure it out.

It is very common, with real problems, that you have to start out with no clear idea how the endpoint is to be reached, you should get used to it ... in this case it is not immediately obvious how to get the number of oscilations from the conservation of energy ... but as you start writing down the expressions and thinking about what you know about how energy works for this system, you'll start to see possible relationships ... like the amount of energy lost related to the distance traveled in half a swing.

BTW: you can actually use the differential equation approach you started with - I don't think there is a way through to the solution that you would consider non-messy.

Learning to play about, to explore the models you use, is the point of the exercise.
 
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Nathanael said:
Do you have the answer? If so can you please share it? I'd like to check my answer.

Try writing a sequence (if that's the correct term) for the amplitude after half-oscillations (if that makes sense).
For m=0.5kg,friction coefficient=0.1,a=3cm and k=2.45N/cm the number of oscillations is 3.5
 
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