How many ways to get a Four of a kind?

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The discussion focuses on calculating the number of ways to achieve specific poker hands, particularly Four of a Kind, Full House, and Two Pairs. The calculations provided for each hand type are scrutinized, with the user expressing uncertainty about their accuracy. The responses affirm that the calculations appear correct, indicating a solid understanding of combinatorial principles in poker. Additionally, the user explores scenarios involving fewer cards dealt, such as obtaining one pair from three or four cards. Overall, the conversation highlights the mathematical approach to poker hand probabilities and confirms the user's calculations.
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Poker hands...

1. How many ways are there to obtain these three highly-rated combinations below?
a. Four of a kind. -Four cards of the same rank and one other card

b. Full House. -Three cards of the same rank and two cards both of another rank. ( A triple, or three of a kind, and a pair.)

c. Two pairs. -Two pairs of cards of two distinct ranks and a fifth card of another rank.

2. Suppose you play a game in which only three cards are deal: How many ways are there to obtain one pair?

3. Suppose four cards are dealt. How many ways are there to obtain one pair?

am i doing these correctly?
1a. 13C1 X 48C1 = 624
b.13C1 X 4C3 X 12C1 X 4C2 = 3744
c.13C2 X 4C2 4C2 44C1 = 123,552

2.13C1 X 4C2 X 12C1 X 4C1 = 3744

3. 13C1 X 4C2 X 12C1 X 4C1 X 11C1 X 4C1 = 164736

am i right?
 
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Hmm, a flash review of your answers suggests to me you are correct

-- AI
 
You seem to know what you're doing gillgill. So why the doubt?
 
thanks...
 
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