How Much Charge Does the Second Charge Have?

AI Thread Summary
The discussion revolves around calculating the charge of a second point charge based on the electric field produced by two charges. The first charge, located at the origin, is given as 1.11 x 10^-5 C, and the electric field at a point 9.11 m away is measured at 1.59 x 10^3 N/C. The initial attempt to use Coulomb's law to find the second charge, Q2, was incorrect as the wrong equation was applied. The correct approach involves using the electric field equation for point charges. Ultimately, the correct value for the second charge was determined to be 2.44 x 10^-6 C.
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Homework Statement


Two charges, one at the origin and one at x=1.6 m produce a field 1.59x10^3N/C at x = 9.11 m. The charge at the origin has a charge of 1.11 x 10^-5 C. How much charge does the second charge have?

http://books.google.com/books?id=vN...the origin has a magnitude of 845 N/C&f=false

Page 96 Question 3.49

Homework Equations



E=F/q
E=kq1q2/r^2
k=8.99x10^9


The Attempt at a Solution



I tried using coulomb's law to find Q2

1590=(9x10^9)(1.11x10^-5)(q2)/(9.11^2)

But my solution did not match the answer which was q2 = 2.44x10^-6C
 
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That's not the correct equation for the electric field due to a point charge. You have the equation for the force between two point charges. It's not really useful for this problem.
 
ah yes i got it ty
 
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