How much current does a cell phone use?

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SUMMARY

The discussion centers on the current consumption of cell phones, specifically comparing it to the voltaic pile. A typical lithium-ion battery in a smartphone, such as the iPhone 4 with a 3.7V and 1400mAh capacity, averages around 100mA during use, while higher demands can push it to 600mA or more. Factors affecting current draw include signal strength and background processes, which can cause fluctuations in power consumption. Tools like the Ampere app can provide real-time current measurements, revealing that smartphones can draw anywhere from 300mA to 1.8A depending on usage.

PREREQUISITES
  • Understanding of lithium-ion battery specifications (e.g., voltage, capacity)
  • Familiarity with smartphone power management and background processes
  • Knowledge of current measurement tools (e.g., Ampere app)
  • Basic principles of electrical resistance and current flow
NEXT STEPS
  • Research the power consumption specifications of modern smartphones
  • Explore the functionality of the Ampere app for monitoring current usage
  • Investigate the impact of signal strength on smartphone battery life
  • Learn about the electrical characteristics of the Simcom SIM900 GSM module
USEFUL FOR

This discussion is beneficial for electronics enthusiasts, smartphone users interested in battery performance, and developers working on mobile applications that require efficient power management.

Cool4Kat
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I am doing a series of videos on the history of electricity and I am working on a video on Volta and the first battery.

Anyway, I want to compare the voltaic pile to a typical li-ion battery running my iPhone. Now the voltaic pile could easily create 20 V of potential but it had high internal resistance and would max out at around 15 mA of current.

I can easily find the voltage of the battery but I have no idea how much current it regularly uses! Nor do I know how much it needs for high power items like downloading pictures. Any help? Any idea where I could find the answers? Thank you so much!
 
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See if you can find a third-party supplier of replacement batteries and hope they list battery AmpHour (AH) capacity. (You might get lucky and be able to get that info from a phone dealer or distributor, but don't hold your breath!) When you find that, look at the advertising or user manual for the phone to find the battery run time, in hours, between charges. Divide the battery AH capacity by the run time to estimate the battery current. The estimate will be off by a factor of two to four, could be either high or low (thanks to advertising and battery life considerations.)

Another confounding factor is if the phone is receiving a weak (or no) signal from the cell tower it transmits at maximum power, drawing more current. Conversely, with a strong cell tower signal it will reduce transmit power to conserve battery charge

Now you've got me curious, when/if you find an answer please let us know the estimate in a followup post here.

Tom
 
Google for power requirements of the Simcom SIM900 - GSM module that could be used in simple DIY electronics projects. While it doesn't have to be representative of all similar devices, it is definitely an example of them.

I can't find the datasheet at the moment, apparently there were some shifts in the ownership, sites moved and most links I stumble upon are broken. If memory serves me well it can draw more than 2 A during initialization, 250 mA typically (whatever it means) and some single mA in sleep mode.
 
The battery in my cell phone is 3.7 volts at 2100 milliamp-hr (2.1 amp-hrs). That will last for, IDK, maybe four hours of continuous talking. The average current would then be 2100 mah / 4 hours = 500 milliamps. The instantaneous current will be higher when transmitting, and lower when receiving. This is a SWAG, somebody else may have better numbers. But at least it's better than a WAG.
 
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I followed Tom's advice and looked up the specs for a phone this is what I got:

I found the specs for the iPhone4 (admittedly a little behind the times but that is OK). It's battery is 3.7 Volts and has a capacity of 1400mAh. It would provide 14 hours of phone and 10 hours of wifi. So that means, on average, the phone used 100 mA and the wifi used 140 mA. I think I am going to say that a cell phone needs to be able to provide about 150mA of steady current for many hours, and the Voltaic pile can only produce a steady current of like 1 mA (although it can do a maximum of 15 mA but only for like a half a minute). Surprisingly, a little LED light bulb will visibly glow with just 0.1 or 0.2 mA of current so you can't use a stack of pennies to run your phone but you can use it to light up an LED!

I will try to look up more modern specs but they will be out of date in 4 months anyway!
 
I have an obviously named app on my phone that tells me at this second it is drawing 1.8Amps.
 
What’s the name of the app??
 
Cool4Kat said:
What’s the name of the app??
Ampere.
 
This is kinda late but on ampere it says that my phone is draining 300ma, about a minute ago it was 600ma. I am unusre why it changed since I was sitting there staring intently at the amperage on the app, and nothing else
 
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Stephenk53 said:
This is kinda late but on ampere it says that my phone is draining 300ma, about a minute ago it was 600ma. I am unusre why it changed since I was sitting there staring intently at the amperage on the app, and nothing else
A cell phone is a tiny computer. It is doing all sorts of things in the background. Maybe it was pinging Facebook for updates.
 
  • #11
Stephenk53 said:
This is kinda late but on ampere it says that my phone is draining 300ma, about a minute ago it was 600ma. I am unusre why it changed since I was sitting there staring intently at the amperage on the app, and nothing else

russ_watters said:
A cell phone is a tiny computer. It is doing all sorts of things in the background. Maybe it was pinging Facebook for updates.

Yes, and it is also regularly pinging and being pinged by the nearest cell tower to confirm connectivity, location and ID etc
those little bursts of transmit and receive ... specially the transmit, will increase the observed current usage
 
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