How Much Does a Spring Compress Under a 10-N Force?

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Homework Help Overview

The problem involves determining the compression of a spring when subjected to a force of 10 N, given a spring constant of 400 N/m. The context is rooted in the principles of mechanics, specifically Hooke's Law and Newton's laws of motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between force and spring compression, referencing the spring constant and the concept of displacement. There are attempts to clarify the application of Hooke's Law and the implications of Newton's first law in this context.

Discussion Status

Some participants have provided insights into the relationship between the applied force and the resulting spring compression, while others express confusion regarding the concepts being discussed. The conversation is ongoing, with various interpretations of the problem being explored.

Contextual Notes

There appears to be a lack of clarity regarding the application of the spring constant and how it relates to the force applied. Participants are questioning the assumptions made in the problem setup and the definitions involved.

kallied
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Homework Statement


if a 10-N force is used to compress a spring with a spring constant of 4.0x10^2N/m, what is the resulting spring compression?


Homework Equations





The Attempt at a Solution

 
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The spring constant tells you something about how great a force is needed to compress the spring 1 m so see if the units give you a hint. It is just a ratio.
I think the problem is about finding the dx (The displacement). Alternativly use Newtons 1. law to see where it stands still, and the force seems constant to me:
Fhook - Fpress = 0 => kx - Fpress = 0 <=> x = Fpress/k
Do you get the idea?
 
no not really :(
 
What the spring constant says is: for each meter the spring is compressed, the spring will push back with 400 Newtons more force. The spring in your problem will push back with 400x Newtons of force, where x is the distance you compress it in meters. To get your answer, you must find the compression (x) where this spring exerts 10 Newtons of force.
 
Try imangining you compressing a spring. If you pressed with 10 N, then the spring would try to oppose it(You can feel it trying). If you pressed it until it was half as wide as initially, and stood still there, then the acceleration of the spring equals zero(a=0). Then Newtons first law of motion states:
[itex]\sum F = 0[/itex]
The two forces are in opposite directions(you pressing and the spring pressing against)
[itex]Fhook-Fpress = 0 \,\Leftrightarrow \\ kx -10N = 0\\<br /> kx = 10N[/itex]
 

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