How Much Energy is Needed to Heat LNG from -165°C to 5°C?

AI Thread Summary
To heat 50ml of liquid natural gas (LNG) from -165°C to 5°C, specific heat, heat of vaporization, and density are crucial factors. The formula Q=MC(T2-T1) is applicable, but additional calculations for phase changes are necessary. The total energy required includes three components: heating from -165°C to the boiling point, vaporization, and heating from the boiling point to 5°C. Using worst-case scenario values for specific heat and heat of vaporization, an estimated energy requirement of approximately 30kJ was calculated. This approach highlights the importance of accurate thermodynamic properties in energy calculations for LNG.
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Homework Statement


I have liquid natural gas, or LNG, at -165degrees Celsius. I want to know the total energy required to heat the gas up 50ml to 5 degrees Celsius.


Homework Equations


Not sure.
Im assuming I need information regarding specific heat etc. Heat of vaporization maybe?

The Attempt at a Solution


Tried to hunt down some more data on LNG but couldn't find it. I do remember a formula from my high school days a long the lines of Q=MC(T2-T1). Not sure however if that only applies to solids?
 
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total energy = H1 + H2 + H3

H1 = (Cp x mass x (bp - (-165oc))
H2 = (heat of vap x mass)
H3 = (Cp x mass x (5oC - bp)

Yes you will need density, specific heat and Heat of vap of the LNG (and b.p of course) - don't know if it will be good enough to use the methane values though
 
Ok I needed a fair amount of safety, so I used worst case scenarios of Cp being 2.5J/kg.K and Vap being approx 600kJ/kg. The specific gravity was 0.6.

I calculated it to being approx. 30kJ. Does that sound correct?
 
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