How much force is in this bar? Am I correct?

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The discussion centers on calculating the forces in two wires supporting a 15 kg bar. The calculated weight of the bar is 147.15 N, with L1 carrying 49 N, leading to the assumption that L2 should bear the remaining force of 98.15 N. Participants clarify that the forces in L1 and L2 can differ due to the bar being in equilibrium, where the sum of forces equals zero. The varying forces are attributed to concepts of torque, which will be explored in future studies. Understanding these principles is essential for grasping the dynamics of forces in static systems.
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Homework Statement



Once again I am having trouble with a rather simple problem.



This bar above with the mass of 15 Kgs hangs in 2 threads/wires. The force in L1 is 49 N, what is the force in L2?


Homework Equations





The Attempt at a Solution



My solution is this; 1 Kg here on Earth is 9.81 Newtons. So by simply multiplying 15kg with 9.81 I get 147.15 N. The force in L1 is 49 N so is the force in L2 should be 98.15 N?

Homework Statement



I am new to physics but I find it very interesting. The thing I wonder about, according to my solution the major force is in L2 with 98.15 N and by looking at the picture L1 seems to be carrying the major part of the bar so shouldn't L1 have the most force?

Homework Equations





The Attempt at a Solution



 
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Your solution is correct. Because the bar is in equilibrium, the sum of all the forces must be zero.

As to why there are different forces in L1 and L2, that you will learn later, when you come to torques (A.K.A. moments of forces).
 
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