How Much Force is Needed to Move a 50kg Box with Friction and Acceleration?

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To calculate the horizontal force needed to move a 50kg box with an acceleration of 0.620 m/s² on a surface with a coefficient of friction of 0.110, first determine the frictional force using the normal force. The normal force equals the weight of the box, which is 50kg multiplied by gravity (9.81 m/s²). Apply Newton's second law (F=ma) to find the net force required for the desired acceleration. The total applied force must equal the net force plus the frictional force. This approach clarifies that the applied force is the sum of the net force and the frictional force acting against it.
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Hello everyone... I have been having some issues with this one particular... I'm sure its very simple, I just can't rap my head around it!Calculate the horizontal force required to move a 50kg box across level floor with an acceleration of 0.620 m/s/s if coefficient of friction is 0.110

FORCE = ??

I think its the acceleration that is throwing me off here. Would i need to find my Frictional force then determine my Fnet?

Thanks in advance for the aid.

-Stephan
 
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Hello >:D
Hmm a basic question indeed :D
The block is lying on rough horizontal surface.When an Force is applied, the Static friction,fs will come into play and try to oppose the relative motion.fs will increase as applied force is increased.But fs got a max. value (coef. of friciton)*(normal rxn by surface applying frictional force) and after that Kinetic friction will act and have value same as (coef. of friciton)*(normal rxn by surface applying frictional force)
Let the force applied Be F , Kinetic friction in opposite direction of F and apply Newton's second law .
U will get the answer :D

Hope this helps:)
 
Knowing both mass and acceleration you should find fnet using F=ma. This value plus the frictional force must equal the applied force so simply use the mass to find the normal force to get frictional force.
 
this is a easy problem al this means is to move the box forward your applied force will be Fnet+Ff.
hope this helps!
 
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