How Much Force Must a Tractor Exert to Pull a Sled Up a Hill with Friction?

AI Thread Summary
To determine the minimum force a tractor must exert to pull a 5000kg sled up a 30° hill at constant velocity, one must consider both the gravitational force acting on the sled and the frictional force of 10,000 N. A free body diagram is essential for resolving the gravitational force into components parallel and perpendicular to the slope. The force along the slope due to gravity must be calculated and then counteracted by the frictional force to find the total force required. By analyzing these forces, the necessary exertion by the tractor can be accurately determined. Understanding these dynamics is crucial for effective problem-solving in physics.
Richard1864
Messages
1
Reaction score
0
A tractor pulls a 5000kg asked up a hill at a constant velocity. If the hill had a constant grade of 30° with respect to the horizontal and there is a 10,000 N frictional force between the sled and the ground, what is the minimum force the tractor must exert on the sled?

I think I'm supposed to tilt the axis. The Friction is already given so how do I find the force required?
 
Physics news on Phys.org
Draw a freebody diagram, resolving gravity along a set of coordinate axis parallel and perpendicular the the slope. This will give you the the force along the slope due to gravity, which needs to be counteracted by friction.
 

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Acceleration = (Force of boy on sled - Force of friction)/Mass of sled
Replies
3
Views
2K
Inclined plane problem strange result
Replies
3
Views
6K
Sledding Down a Hill - Speed Calculation
Replies
5
Views
2K
Why is the velocity at the cusp point equal to the final velocity on the hill?
Replies
10
Views
2K
Calculating Acceleration of a Sled on an Incline with a Pulling Dog
Replies
4
Views
2K
What is the coefficient of friction in a child pulling a sled up an incline?
Replies
3
Views
2K
Sledding Down a Hill: Calculating Friction and Velocity
Replies
31
Views
3K
Size of the friction force felt?
Replies
4
Views
2K
Friction of a sliding box on a slope
Replies
11
Views
2K
Work and Kinetic Energy of a Sled
Replies
4
Views
5K

Hot Threads

Recent Insights

Back
Top