How Much Force to Accelerate a Box with Known Friction?

Thread starter BiG mAnN
Start date Nov 16, 2005
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Coefficient Coefficient of friction Friction

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To determine the horizontal force required to accelerate a 4.0 kg box with a coefficient of friction of 0.60 at 2.0 m/s², first calculate the friction force using the formula: friction force = coefficient of friction * normal force. The normal force equals the weight of the box, which is 4.0 kg multiplied by gravity (9.81 m/s²), resulting in a normal force of approximately 39.24 N. The total force needed can be found by applying Newton's second law (F = ma), which gives a force of 8 N for acceleration. Adding the friction force to this total yields the necessary horizontal force to overcome friction and achieve the desired acceleration.

Nov 16, 2005

BiG mAnN

I need help on this question, The coefficient of friction between a 4.0 kg box and the floor is 0.60. How large of a horizontal force is necessary to give the box an acceleration of 2.0m/s²?

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Nov 16, 2005

thowonasweaterandgo

that sounds suspiciously like a homework problem

Nov 16, 2005

thowonasweaterandgo

Friction force = (coefficient of friction) * (normal force)
F = ma

all you need

Nov 16, 2005

vanesch

Staff Emeritus

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thowonasweaterandgo said:

that sounds suspiciously like a homework problem

Yeah ! Movin' it...

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