How Much Force to Hold a Fire Hose Delivering Water at High Speed?

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A fire hose delivering water at high speed exerts a significant force on the holder due to the acceleration of water through the nozzle. The discussion involves applying the continuity equation and Bernoulli's equation to calculate the velocities in the hose and nozzle, resulting in a pressure calculation of approximately 857,830 Pa. The force required to hold the hose was computed as 3,789.8 N, but this answer was questioned for accuracy. An alternative approach suggested involves analyzing the change of impulse of a small mass of water to determine the force needed. The conversation highlights the complexities of fluid dynamics in practical firefighting scenarios.
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1. A fire hose exerts a force on the person holding it. This is because the water accelerates as it goes from the hose through the nozzle. How much force is required to hold a 7.5 cm diameter hose delivering 470 L/min through a 0.80 cm diameter nozzle?

Homework Equations



I think we need to use the continuity eqn: A1V1 = A2V2 = Q
and the Bernoulli eqn: P + (rho)gh + 1/2 (rho)v^2 = constant

The Attempt at a Solution



Using the continuity equation, I found the velocities in the nozzle and in the hose
V1 (in nozzle) = 38.97 m/s
V2 (in hose) = 1.77 m/s

Then I used the bernoulli equation to solve for the pressure in the hose.
P1 = P2 + 1/2 (rho)[(v2)^2-(v1)^2]
with P2 = 1.0*10^5 Pa
P1 = 857830.4646 Pa

Then I said P = F/A
F = PA = 857830.4646 Pa(Area of hose)
F = 3789.8 N

But this is the wrong answer - I wonder if my logic itself is faulty?
 
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Have you tried using the change of impulse of a small mass dm of water instead? This change of impulse should be equal to the force the brave fire fighter is using to hold the nozzle.
 
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