How much heat is generated from lost mechanical energy?

[willydavidjr]

Let the mechanical equivalent of heat be 4.2[J/cal]. 70 percent of lost mechanical energy was converted into heat. Find the generated heat quantity given an object with mass 10 kg moving at speed 49 m/s with coefficient of kinematic friction 0.5 and gravitational acceleration of 9.8 \frac{m}{s^2}.

 

[Hootenanny]

Let the mechanical equivalent of heat be 4.2[J/cal]

Joules per calorie?

 

[willydavidjr]

Yes Hootenanny! I really cannot get it because the givens are quite unique and confusing.

 

[Hootenanny]

I think there's a typo in the question because the units of J/cal are nonsensical. Heat is 'energy in transit' therefore the SI units are Joules.
Regards,
~Hoot

 

[willydavidjr]

I am trying to solve the problem but all I can get is the stopping distance. I am still researching for the formula for the time respected to the problem.

 

[Hootenanny]

Nevermind, I have seen my mistake. If you have calculated the stopping distance you have all the information you need.

HINT: What is work done?

Regards,
~Hoot

 

[willydavidjr]

Can I use the formula x-x_o=v_ot + \frac{1}{2}at^2 to get the stopping time?Or is there any other formula?

 

[Hootenanny]

If you have calculated the stopping distance, you have all the information you need. Work done = force times distance. In this case work done = energy 'lost'.

Regards,
~Hoot

 

[willydavidjr]

If I get the work with this= 0.5 * 10 kg * 9.8 \frac{m}{s^2} * 255 m, then what is the purpose of the given "mechanical equivalent of heat be 4.2[J/cal]. 70 percent of lost mechanical energy was converted into heat"?

 

[Hootenanny]

You should get 245m, but 255 is close enough. You have calculated the energy lost. However, only 70% of this 'lost' energy is converted into heat...

Regards,
~Hoot

 

[willydavidjr]

Yeah you're really right. That was really close enough for the stopping distance. But how can I compute for the generated heat quantity given the mechanical equivalent of heat be 4.2[J/cal]. The final answer is suppose to be in calorie unit.

 

[Hootenanny]

Ahh, I think what they question meant was 1 calorie = 4.2 Joules.

Regards,
~Hoot

 

[willydavidjr]

Now I get it buddy. 12495 Joules is the work done or the energy lost and I will multiply it by 0.70 to get the 70 percent lost. I get 8746.5 Joules. Dividing it by 4.2 j/cal gives me 2082.5 cal. Is 2082.5 right buddy?

 

[Hootenanny]

Yep, that looks good to me.

Regards,
~Hoot

 

[willydavidjr]

Thanks Hoot. You were a great help to me. Till next time.