How Much Impulse Is Needed to Stop a Baseball with Unrealistic Momentum?

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To stop a baseball with a momentum of 900 kg m/s, an impulse equal to that momentum is required, meaning the outfielder must apply an impulse of 900 Ns. Given a maximum force of 100 N, the time needed to exert this force can be calculated using the impulse-momentum theorem. However, the momentum value presented seems unrealistic, as it implies an extremely high velocity for a baseball, estimated between 3000 to 4500 m/s. This suggests a potential error in the initial momentum figure, as typical baseballs have a mass of about 0.2 to 0.3 kg. Clarifying the momentum value is essential for accurate calculations.
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If a baseball were flying towards an outfielder with a momentum of 900 kg m/s. What impulse would the outfielder need to apply to bring the ball to a stop? AND If the maximum force the dude can exert is 100N for what length of time will he have to exert this force?
 
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This sounds like a homework question.
Please post it in the homework forums and they can help you there.
 
I think there is something wrong with your number. I don't know the mass of a baseball but I would guess about 0.2 to 0.3 kg.
To have a momentum of 900 kg m/s means a velocity of 3000 to 4500 m/s and that does not sound reasonable
 
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