How much will he weigh on a different planet

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To determine the weight of a space traveler on another planet, the gravitational force formula F = G(m1 * m2) / r^2 is relevant, where m1 is the mass of the planet and r is its radius. The traveler weighs 500 N on Earth, and the new planet has a radius three times that of Earth and a mass twice that of Earth. The weight on the new planet can be calculated by considering the changes in radius and mass, which affect gravitational force. Specifically, the increased mass would increase weight, while the increased radius would decrease it. Ultimately, the combined effect of these factors will yield the traveler's weight on the new planet.
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Homework Statement



A space traveler weighs 500 N on earth. What will the traveler weigh on another planet whose radius is three times that of Earth and whose mass is twice that of earth?

answer in Newtons

Homework Equations





The Attempt at a Solution




i think the formula looks something like this, F = G(m1 * m2) / r^2 but I'm wrong somehow, also there are missing variables. This problem does not look very hard, just need help setting it up.
 
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You could do it that way, but you don't actually have to do the numbers.

You are given two factors affecting your weight. What effect does each of them (individually) have generally/algebraically on your weight (as related to Earth=1)?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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