How Much Work Did the Hamster Do on the Exercise Wheel?

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The discussion revolves around calculating the work done by a hamster on an exercise wheel. The hamster runs at a speed of 0.8 m/s, and the wheel is characterized by a radius of 0.10 m and a mass of 5.9 g. Participants suggest using the relationship between rotational energy and work, emphasizing that the work done equals the change in rotational energy. The formula for rotational energy, E_rot = 1/2 I ω², is highlighted as crucial for the calculation. The conversation focuses on understanding the correct application of these physics principles to determine the work done by the hamster.
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After getting a drink of water, a hamster jumps onto an exercise wheel for a run. A few seconds later the hamster is running in place with a speed of 0.8 m/s. Find the work done by the hamster to get the exercise wheel moving, assuming it is a hoop of radius 0.10 m and mass 5.9 g.


I'm not sure how to solve this one. I think you use

Work=(torque) x (delta theta)

Torque = rF

but, after that, I'm not sure what theta would be. Am I even using the right set of equations? Thanks for all the help! :smile:
 
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All you need to do is compare the rotational energy before and after! That will equal the amount of work the hamster did. The rotational energy is half the product the moment of inertia and the square of the angular velocity.

Thanks to ehild for catching my missing 1/2!
 
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Tide said:
All you need to do is compare the rotational energy before and after! That will equal the amount of work the hamster did. The rotational energy is the product the moment of inertia and the square of the angular velocity.

half of this...

E_{rot}=\frac{1}{2}I\omega^2



ehild
 
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