How Much Work Is Done Pulling a Wagon at an Angle?

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The discussion focuses on calculating the work done while pulling a wagon at a 30-degree angle with a force of 200N over a distance of 2km. The formula used is W = FΔx(cosθ), leading to a calculated work of 346,410 J or 346 kJ. Participants confirm the accuracy of the calculation and emphasize the importance of descriptive thread titles for clarity. The conversation highlights the application of physics principles in practical scenarios. Overall, the thread serves as a helpful resource for understanding work done against non-conservative forces.
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Homework Statement


Kids are pulled 2km around a town in a wagon,The handle of the wagon is on an angle of 30 degrees from horizontal and requires 200N to maintain constant velocity. Determine the amount of work done against non‐conservative forces on this walk.

Δx = 2km = 2000m
angle θ = 30
Fapp = 200N

Homework Equations


W= fΔx(cosθ)

The Attempt at a Solution


W= 200(2000)(cos30)
=346410 J
=346 KJ
 
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Hi Valenti, Welcome to Physics Forums.

Your calculation looks fine.

Please note that thread titles should reflect the nature of the problem and the area of physics involved. "Homework check" doesn't do that. I've changed your thread title to "Work done pulling a wagon" to be more descriptive of the content.
 
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