How Much Work is Done Pushing a Sled Up an Incline?

AI Thread Summary
To determine the work done pushing a sled up an incline, the force must be calculated using the sled's weight and the incline's angle. The sled, with a combined weight of 35 kg, exerts a force of 343 N due to gravity. The normal force is then adjusted for the incline using the cosine of 15 degrees. The definition of work is clarified as W = Fd or W = Fd cos(theta), which is essential for solving the problem. Understanding these concepts is crucial for accurately calculating the work done against gravity and friction.
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Homework Statement


FATHER PUSHs IS DAUGHTER ON A SLED UP A SNOWY INCLINE. IF THE SLED MOVES UP THE HILL WITH A CONSTANT VELOCITY how MUCH WORK IS DONE?
CHILD & SLED= 35KG FRICTION OF SNOW & SKIDS= .2 INCLINE= 15 DEGREES, d=10 m

Do i need to find the force? (N=mg)
and then Ncos15degrees?


The Attempt at a Solution


I don't know how to get started.
 
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Have you made any attempt to answer this question? You must show some work before we can help you. Also, in future, would you please write in lower case: upper case is considered to be shouting.
 
Yes I have, but I'm not getting the same answer as in the book.
Sorry about the upper caps.
 
35kg*9.8= 343N
343N cos 15 degrees = .97
 
What is the definition of work?

Casey
 
definiton of work is W=Fd
 
or W=Fd = (Fcos thete)
 
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