How Much Work Is Needed to Move a Charge in an Electric Field?

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To calculate the work needed to move charge q2 from (0.180 m, 0) to (0, 0.370 m) in the electric field created by charge q1, one must consider the potential energy at both positions. Since the electric force is conservative, the work done is determined by the difference in potential energy, expressed as W = -ΔPE. It is important to note that work is only done when the distance r changes, as moving along an equipotential surface requires no work. The equation W = F DOT d applies when force is constant; otherwise, integration is necessary to account for varying force over the distance. Understanding these principles allows for the correct calculation of work in electric fields.
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A positive point charge q1 = 2.30uC is located at the origin (x=0, y=0). The charge is held fixed. Another point charge q2 = 5.60uC starts at the point (0.180 m,0). What is the magnitude of the work required to move q2 to
(0,0.370 m) (in J)?

How do I do this?

I know W =Fd, but I don't think I can use the equation F = (k1q2)/r^2, because the distance is constantly changing.

Can anyone at least give me a hint or some insight?
 
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Remember, the electric force is conservative. That means that the path traveled does NOT affect the total work done. It's simply a matter of where the point starts, and where it ends. Find the potential energy at each place, and W = -\Delta PE.

Note that work is only done when r changes, by the way. Otherwise, the charge is traveling on an equipotential surface, and you get to move it around for free.

Also, W = F DOT d, which is an important distinction.
 
Indeed, W=Fd holds only if F is constant. If F changes over the distance, you have to cut the distance into many small pieces and take F to be constant over each piece and sum up the contributions. In other words: integrate.
 
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