How much zinc sulfide is produced from 5.0 g of Zn and S?

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To determine how much zinc sulfide is produced from 5.0 g of zinc and 5.0 g of sulfur, a balanced chemical equation is necessary, specifically Zn + S → ZnS. The next step involves identifying the limiting reagent by converting the masses of zinc and sulfur into moles. The law of constant composition indicates that the elemental makeup of zinc sulfide will remain consistent regardless of the amounts used. Understanding the stoichiometry of the reaction is crucial for calculating the final yield of zinc sulfide. Proper conversion from grams to moles is essential for accurate results.
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Homework Statement


5.0 g of Zn is heated with an equal amount of S, bow much zinc sulfide is produced?

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The Attempt at a Solution



Wouldn't there be an equation to solve this problem? I know law of constant composition is an observation that the elemental composition of a pure compound is always the same.
 
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By equation do you mean a chemical equation?

You have 5.0 g of Zn and 5.0 g of S, you need to find out which is the limiting reagent.
 
Okay, then do you have to do a balanced chemical equation?
 
I would start with that first.
 
5 Zn --> 5 S

Do you mean something like this? I really do appreciate this alot, thanks for your help
 
Zn and S are the reactants, so they go on the left side.

Zn + S → ZnS
(now you know what the equation is)

The masses of the reactants don't have a part in the equation itself at all.
 
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ok thanks a lot for this
 
Do you know how to convert grams of a substance to moles? I would first start changing all the grams to moles.
 
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