How Should a Plane Adjust Its Course in Crosswinds to Fly Due North?

AI Thread Summary
To fly due north in crosswinds, a plane must adjust its course to 48.7 degrees east of north. The plane's airspeed is 206 km/h, while the wind speed is 76.6 km/h at the same angle. When accounting for the wind, the plane's ground speed is reduced to 166 km/h. A vector diagram can effectively illustrate the relationship between the plane's speed and the wind. Thus, the correct flying angle and resultant ground speed are crucial for maintaining the desired course.
greyradio
Messages
12
Reaction score
0
A plane is flying at a speed of 206 km/h in still air. There is a wind blowing at a speed of 76.6 km/h at 48.7 degrees to the east of north, and the pilot wishes to fly due north.

What angle should the plane fly? (assume the angle is measured between the plane and north.)
What speed does the plane fly relative to the ground with the wind blowing?I've tried drawing the vector diagram but I'm having trouble with it. I initially assumed the plane would be flying in a straight line from west to east. However, quickly realized that this created a right triangle where the hypotenuse is 76.6 km/h which is not possible as the largest vector is 206 km/h. My other attempts to solve it have failed. I was hoping someone could help me out. Thanks.
 
Last edited:
Physics news on Phys.org
The angle that the plane should fly is 48.7 degrees east of north. The speed of the plane relative to the ground with the wind blowing is 166 km/h.To solve this problem, you can draw a vector diagram. The vector for the plane's speed is 206 km/h at 0 degrees (due north). The vector for the wind is 76.6 km/h at 48.7 degrees (east of north). To find the total vector, add these two vectors together to get 166 km/h at 48.7 degrees. This is the direction and speed the plane should fly relative to the ground with the wind blowing. Therefore, the angle the plane should fly is 48.7 degrees east of north.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top