How Should Motion Be Initiated in a Lightly Damped Spring System?

tjr39
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[SOLVED] Lightly damped spring system Q

Homework Statement



Consider a lightly damped mass-on-a-spring vibrational system. How should motion be initiated so that the amplitude of the spring is given by;

\Psi(t)=Ce^{-\frac{\lambda}{2}t}Cos(\omega_{r}t+\pi)

Homework Equations





The Attempt at a Solution



I don't really know what is being asked "how should motion be initiated". Anyways I tried finding the solution at t=0,

\Psi(0)=Ce^{-\frac{\lambda}{2}*0}Cos(\omega_{r}*0+\pi)

Which simplifys to \Psi(0)=-C (as e^{0}=1 and Cos(\pi)=-1)

So is my answer just the spring should be stretched by aplitude C to give above equation of displacement? Thanks.
 
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Also find the initial velocity by d\psi/dt.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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