How to Avoid Common Mistakes in Solving Forces Problems?

  • Thread starter Thread starter FaraDazed
  • Start date Start date
  • Tags Tags
    Forces Resolution
Click For Summary

Homework Help Overview

The problem involves determining the resultant force acting on a particle influenced by two forces, specified by their magnitudes and angles from north. The subject area pertains to vector addition in physics, particularly in the context of forces.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to resolve the resultant force using trigonometric functions but expresses confusion regarding the correct application of sine and cosine. Some participants suggest visualizing the problem with vector diagrams to clarify the situation.

Discussion Status

The discussion includes reflections on the original poster's calculations and the realization of a common error related to calculator settings. Participants are engaged in exploring the implications of this mistake and its effect on the results, with no explicit consensus reached on the overall approach yet.

Contextual Notes

There is mention of the original poster's confusion regarding the use of trigonometric functions and the importance of ensuring calculator settings are correct, which are common pitfalls in solving such problems.

FaraDazed
Messages
347
Reaction score
2

Homework Statement


A particles is under the influence of two forces, 500N at 50° from north and 350N at 350° from north. Find the magnitude and direction of the resultant pull on the particle.

Homework Equations



?

The Attempt at a Solution


[itex] x=500cos40-350cos80\\<br /> x=322.25N\\<br /> y=500sin40+350cos10\\<br /> y=666.08N \\<br /> <br /> \sqrt{322.25^2 + 666.08^2}=739.94N \\<br /> arctan(322.25/666.08)=25.82° from north. \\[/itex]
I am a bit confused on when to use cos or sin. The above is how a classmate pursaded me to change it to but on my first go I had
[itex] x=500cos40-350sin10 \\<br /> <br /> y=500sin40+350cos10 \\[/itex]
 
Last edited:
Physics news on Phys.org
Draw the vectors on an x-y plot (+y = North). It should be obvious from that.
 
rude man said:
Draw the vectors on an x-y plot (+y = North). It should be obvious from that.

Thanks for your reply. I have already done that and the figure and direction obtained seem correct but I don't know for sure and if my method is correct.

EDIT: Sorry just realized my mistake. They are both the same but doing it a different way, my calculator was set on radians instead of degrees and that is why I was getting different figure to earlier :redface: sorry.
 
Last edited:
FaraDazed said:
..., my calculator was set on radians instead of degrees ...
A very common mistake. Remember to check the setting whenever you have an exam :smile:
 

Similar threads

  • · Replies 18 ·
Replies
18
Views
2K
Replies
3
Views
2K
Replies
12
Views
2K
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 29 ·
Replies
29
Views
4K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 35 ·
2
Replies
35
Views
4K
  • · Replies 5 ·
Replies
5
Views
14K