How to Avoid Common Mistakes in Solving Forces Problems?

  • Thread starter Thread starter FaraDazed
  • Start date Start date
  • Tags Tags
    Forces Resolution
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 2K views
FaraDazed
Messages
347
Reaction score
2

Homework Statement


A particles is under the influence of two forces, 500N at 50° from north and 350N at 350° from north. Find the magnitude and direction of the resultant pull on the particle.

Homework Equations



?

The Attempt at a Solution


[itex] x=500cos40-350cos80\\<br /> x=322.25N\\<br /> y=500sin40+350cos10\\<br /> y=666.08N \\<br /> <br /> \sqrt{322.25^2 + 666.08^2}=739.94N \\<br /> arctan(322.25/666.08)=25.82° from north. \\[/itex]
I am a bit confused on when to use cos or sin. The above is how a classmate pursaded me to change it to but on my first go I had
[itex] x=500cos40-350sin10 \\<br /> <br /> y=500sin40+350cos10 \\[/itex]
 
Last edited:
Physics news on Phys.org
rude man said:
Draw the vectors on an x-y plot (+y = North). It should be obvious from that.

Thanks for your reply. I have already done that and the figure and direction obtained seem correct but I don't know for sure and if my method is correct.

EDIT: Sorry just realized my mistake. They are both the same but doing it a different way, my calculator was set on radians instead of degrees and that is why I was getting different figure to earlier :redface: sorry.
 
Last edited: