How to Calculate Acceleration in a Pulley System with Two Masses?

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To calculate the acceleration in a pulley system with two masses, apply the formula r(T2 - T1) = (I)(a/r), where r is the radius, T2 and T1 are the tensions in the cord, I is the moment of inertia, and a is the angular acceleration. The moment of inertia for the pulley is given as 6.0 kgm², and the radius is 0.50 m. When m1 is 2.9 kg and m2 is 5.3 kg, the correct acceleration can be derived from these values. One participant initially calculated an incorrect acceleration of 1.6 m/s² but later found the correct answer. The discussion emphasizes the importance of showing work to identify where difficulties arise in solving the problem.
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The pulley in Figure P8.59 has a moment of inertia of 6.0 kgm2 and a radius of 0.50 m. The cord supporting the masses m1 and m2 does not slip, and the axle is frictionless.

Find the acceleration of each mass when m1 = 2.9 kg and m2 = 5.3 kg.

Im not sure how to get started. What I did was r(T2 - T1) = (I)(a/r)
I got a = 1.6 but that is wrong
What am I doing wrong?

Nvm,, got the answer. thanks for lookin
 

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i have a question, how did u get the answer? I am really having trouble with that..if you don't mind? :) cuz' i tried a lot and i still don't have the answer...
 
xbabiemuahzx: Show us what you've tried so far and where you are stuck.
 

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