How to Calculate Heat Loss in a Long Cable for a Single-Phase Load?

AI Thread Summary
To calculate heat loss in a long cable for a single-phase load, first determine the current using the formula I = P / (V * PF), where P is power, V is voltage, and PF is power factor. For a 69 kW load at 230 V RMS with a power factor of 0.68, the current is approximately 429.57 A. Next, calculate the total impedance of the cable, which is given as 0.011+j0.005 Ω per phase. The heat loss in the cable can be found using the formula P_loss = I² * R, where R is the real part of the impedance. This approach provides a systematic way to find the heat loss in the cable.
Stivi
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Homework Statement


A 69 kW single-phase load with a power factor of 0.68 lagging is fed by a long cable with an impedance of 0.011+j0.005 Ω per phase. The voltage across the load is 230 V RMS. Calculate the heat loss in the cable in Watt [W].



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The Attempt at a Solution

 
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Stivi said:

The Attempt at a Solution


You might want to start by finding the magnitude of the current I.
 

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