How to Calculate Magnetic Flux Through a Desk?

  • Thread starter Thread starter mrlucky0
  • Start date Start date
  • Tags Tags
    Flux
AI Thread Summary
To calculate the magnetic flux through a desk measuring 4.3 m by 2.0 m in a magnetic field of 0.32 mT directed at 45° below the horizontal, the formula used is Flux = B*A*Cos(a). The calculated flux is 0.00194596 T*m, but the units should be T·(m^2). Concerns were raised regarding the magnetic field strength, as typical values for Earth's magnetic field range from 30 to 60 microteslas (0.03 to 0.06 mT). It is suggested to double-check the decimal placement in the magnetic field value provided. Accurate calculations and correct values are crucial for determining magnetic flux.
mrlucky0
Messages
69
Reaction score
1

Homework Statement



A horizontal desk surface measures 4.3 m by 2.0 m. If the Earth's magnetic field has magnitude 0.32 mT and is directed 45° below the horizontal, what is the magnetic flux through the desk surface?

Homework Equations



Flux = B*A*Cos(a)

Where A is the area, B is the magnetic field,

The Attempt at a Solution



Flux = B*A*Cos(a)
= (.32E-3 T) * (4.3*2.0 m^2) * ( Cos(45) )
= 0.00194596 T*m

However, the my solution isn't correct and I'm convinced that I'm not doing anything incorrectly.
 
Physics news on Phys.org
mrlucky0 said:

The Attempt at a Solution



Flux = B*A*Cos(a)
= (.32E-3 T) * (4.3*2.0 m^2) * ( Cos(45) )
= 0.00194596 T*m

I don't see anything wrong with your calculation either (other than that the units of flux should be T·(m^2).

I am a bit troubled by the value given for the magnetic field strength. For Earth, this value should be more like 30-60 microteslas or 0.03-0.06 mT. Are you sure about the location of the decimal point in the problem?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top