Engineering How to derive equation from RLC circuit?

AI Thread Summary
To derive a linear differential equation for the RLC circuit, start with the equation obtained from Kirchhoff's Voltage Law (KVL): V_in(t) = L(di_L(t)/dt) + i(t)R_A + ∫(i(t)/C)dt + V_o(t). To simplify, differentiate this equation to eliminate the integral, resulting in dV_in(t)/dt = L(d^2i(t)/dt^2) + (di(t)/dt)R_A + (i(t)/C) + dV_o(t)/dt. The objective is to express the equation in a standard form, ay'' + by' + cy = g(x), which requires incorporating the effects of resistances RA and RB. By focusing on the current i(t) first, it can be transformed into a differential equation for V_o(t) using the relationship V_o(t) = i(t) * RB. The goal is to derive the equation in terms of the differentiation operator D and the circuit parameters.
Nat3
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Homework Statement



http://imageshack.com/a/img580/682/z3mt.jpg

Derive a linear differential equation for the above LTI system.

Homework Equations


i_C=C\frac{dV_C(t)}{dt}

V_L=L\frac{di_L(t)}{dt}


The Attempt at a Solution


Using KVL, I can get the following equation:

V_{in}(t)=L\frac{di(t)_L}{dt}+i(t)R_A+\int\frac{i(t)}{C}dt+V_o(t)

However, I don't know where to go from here. All of the differential equations describing LTI systems in my textbook look like:

ay'' + by' + cy = g(x)

Or something similar to that, and then we factor out the y to get something like

(aD^2+bD+c)y = g(x)

Then we factor what's in the parenthesis to find the characteristic roots.

Any advice on how to proceed?
 
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so what operation could you do to that whole equation to get it into a form you feel comfortable with?
 
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Well, I thought about differentiating it to get rid of the integral, which results in:

\frac{dV_{in}(t)}{dt}=L\frac{d^2i(t)}{dt^2}+\frac{di(t)}{dt}R_A+\frac{i(t)}{C}+\frac{dV_{o}(t)}{dt}

But then I don't know where to go from there.. I think it's the V_{in} and V_o terms that are getting me tripped up.
 
Is the objective to find a D.E. that describes Vo(t) when there's a driving function of Vin(t)? Note that the current i(t) depends on RB as well as RA. So RB needs to appear in your equation.

If you find the D.E. for i(t) given Vin(t) (ignoring Vo for the moment), then you can convert it to a D.E. for Vo(t) easily enough since Vo(t) = i(t)*RB.
 
Nat3 said:
Well, I thought about differentiating it to get rid of the integral, which results in:

\frac{dV_{in}(t)}{dt}=L\frac{d^2i(t)}{dt^2}+\frac{di(t)}{dt}R_A+\frac{i(t)}{C}+\frac{dV_{o}(t)}{dt}

But then I don't know where to go from there.. I think it's the V_{in} and V_o terms that are getting me tripped up.

That's what I would have done. I don't know the convention in circuit analysis, but:

\Delta V = V_{out} - V_{in}

And then you're measuring the potential difference.
 
gneill said:
Is the objective to find a D.E. that describes Vo(t) when there's a driving function of Vin(t)? Note that the current i(t) depends on RB as well as RA. So RB needs to appear in your equation.

If you find the D.E. for i(t) given Vin(t) (ignoring Vo for the moment), then you can convert it to a D.E. for Vo(t) easily enough since Vo(t) = i(t)*RB.

The instructions say to derive a linear differential equation describing the circuit I posted, where the equation should be expressed in terms of the differentiation operator D and the circuit parameters (L, RA, RB, etc.)

The next problem is to find the characteristic roots and modes of the system, so I'm pretty sure that I need to get the equation in the standard form of ay′′+by′+cy=g(x), I'm just not sure how to get there :(
 
I think you have it already. You're not asked to solve it right?

edit: gotchya, missed that...
 
Last edited:

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