How to Derive the Equation for an RLC Circuit?

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Discussion Overview

The discussion revolves around deriving the equation for the voltage ratio \( V_{out}/V_{in} \) in an RLC circuit. Participants explore the application of circuit analysis techniques, specifically focusing on the voltage divider formula and its manipulation to achieve the desired equation.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant asks how to derive the equation \( V_{out}/Vin = [RL]/[-[ω][/2]+jω(R/L)+1/(LC)] \).
  • Another participant requests clarification on the circuit diagram, the definition of \( V_{out} \), and the meaning of \( [\omega]/2 \) using LaTeX syntax.
  • A participant provides a link to an RLC circuit diagram for reference.
  • A later reply suggests using the voltage divider formula to derive the equation and proposes a manipulation of the formula to approach the desired result, while expressing uncertainty about the interpretation of the original equation.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the interpretation of the original equation or the steps needed to derive it. Multiple approaches and interpretations are presented, indicating ongoing exploration and uncertainty.

Contextual Notes

Participants express limitations in understanding the original equation due to unclear notation and request further clarification. The discussion includes unresolved mathematical steps and assumptions regarding the definitions used.

Ai En
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how to get this equation:
Vout/Vin = [RL]/[-[ω][/2]+jω(R/L)+1/(LC)]
 
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- Show us the picture of the RLC Circuit your using.
- Tell us how Vout is defined.
- Tell us what [omega][/2] stands for (use the boards LaTeX syntax).
 
http://upload.wikimedia.org/wikipedia/en/1/14/RLC_series_band-pass.svg
 
Hi Ai En,

as a solution you could use the voltage divider formula to get a first equation:
\frac{V_{out}}{V_{in}} = \frac{R_L}{R_L + j \omega L + \frac{1}{j \omega C}}

afterwards if you think that's useful you can try to manipulate this formula until you get the one given to you. Since i can not interpret your given equation (as i said use the LaTeX encoding to be more clear about your formula) i can only guess and did for example multiply the whole formula with \frac{j \omega L}{j \omega L} and the denominator again with \frac{L}{L} that results in:
\frac{V_{out}}{V_{in}} = \frac{j \omega R_L}{L \cdot \left( - \omega^2 + j \omega \frac{R_L}{L} + \frac{1}{C L}\right)}
 

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