How to determine the point of intersection of sine and cosine?

linuxux
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Homework Statement



Im not sure how to start this question: determine the points of intersection between y=sin x and y=cos 2 x for x between 0 and pi.

The Attempt at a Solution



First thing that comes to mind is the eqaute the two, but i don't know how that helps me?
 
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It should help you. And the identities regarding the sin and cos functions should help you more...
 
Particularly an indentity that says cos(2x) is equal to something.
 
thanks I've got it now, but is the only point of intersection in the range at \frac{\pi}{2}? i suppose i could graph it to be sure...
 
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okay, i was solving incorrectly, they will also both be at 30^{o}. i also assumed i would get a "nice" number. thanks.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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