How to Determine the Velocity of a Triangular Block in a Frictionless System?

AI Thread Summary
To determine the velocity of a triangular block in a frictionless system when a smaller block reaches the bottom, the discussion emphasizes using conservation of momentum and energy principles. Participants express confusion about visualizing the interaction between the two blocks, particularly regarding their velocities. It is suggested to focus on the scenario after the smaller block slides off the incline, simplifying the problem. The conversation highlights the importance of defining the speeds of both blocks relative to the ground for accurate calculations. A participant successfully solves the problem using the discussed methods and seeks recommendations for free mathematics software for better equation representation.
Avi1995
Messages
21
Reaction score
0

Homework Statement


A Block of mass m is placed on a triangular block of mass M(as if Fig).Assuming Frictionless surfaces find the velocity of the triangular block when the smaller Block reaches the bottom end.
200tt7k.png


2. Relevant concepts

Centre of Mass,Linear Momentum and probably Conservation of energy concepts

The Attempt at a Solution


I confess , I am quite confused visualising this one. especially the velocity of Big and small black,as
small block is on top of big block so the big block's velocity will also effect the small block.
Any Hint to start, is appreciated.Also Please tell how to visualize these situations. :(
 
Physics news on Phys.org
Rather than worry about the speed while the block is on the incline, just consider things after it slides off. Apply conservation of momentum and energy.
 
Doc Al said:
Rather than worry about the speed while the block is on the incline, just consider things after it slides off. Apply conservation of momentum and energy.

But the problem says when it reaches the bottom end, isn't it before it slides off?
 
Avi1995 said:
But the problem says when it reaches the bottom end, isn't it before it slides off?
In that case it's a tad more complicated, but still the same basic idea. I would call the speed of the block with respect to the wedge v1. Then consider conservation of momentum and energy. (Hint: How would you express the speed of the block with respect to the ground? Call the speed of the wedge with respect to the ground V2.)
 
Thank you so much, Sir. I was finally able to solve the problem using your method.
Although I won't be able to post the solution as it is quite long but the method is same.

PS: Can anyone tell me some good FREE Mathematics Software, so that i am able to write equations easily and graph some functions. I have Microsoft Maths, but I don't quite like it.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top