How to differentiate an integral?

owlpride
Messages
210
Reaction score
0
I just need a short reminder from Calculus. Suppose you have a linear functional \alpha from C1[-1,1] to \Re, given by

\alpha(f) = \int_{-1}^{1}f(t)g(t)dt

for some fixed continuous function g. What is \frac{d \alpha}{d f}?
 
Physics news on Phys.org
\frac{d \alpha}{d f} = \int_{-1}^{1}\frac{d}{df}f(t)g(t)dt
 
Is there any way to simplify (or expand) this?

I am tempted to think that

\int_{-1}^{1}\frac{d}{df}f(t)g(t)dt = \int_{-1}^{1}g(t)dt

but that cannot be right because it's just a constant and integrating it would give me f times a constant instead of an integral involving f .
 
Last edited:
Thanks a lot!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top