How to do intgral for (cos(x)^2)*cos(wx)

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Homework Statement

Homework Equations

The Attempt at a Solution

 
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excuse me
i want integral of cos(x^2)*cos(wx)dx
 
mirshayan said:
excuse me
i want integral of cos(x^2)*cos(wx)dx
I "want" that too. :smile:

1. Are you sure that is the exercise? No typo?
2. Please show your attempt(s) to solve the integral.
 
Samy_A said:
I "want" that too. :smile:

1. Are you sure that is the exercise? No typo?
2. Please show your attempt(s) to solve the integral.

actually its the Fourier cos transforms of cos(x^2)
our teacher ask us To prove it.:headbang::headbang::headbang: i know the answer is what (see the attach file) but i want way
 

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There are probably a number of ways to prove it.

I would start by noting that ##\cos (y)=\frac{e^{iy}+e^{-iy}}{2}##.

But show us how you would try to find the answer, please.
Remember that the real question is not to find the integral of ##\cos(x²)\cos(\omega x)##, but to find the Fourier transform of ##\cos(ax²)##. You could at least start by defining that Fourier transform in the "relevant equations" part of the template.
 
thx alot
Samy_A said:
There are probably a number of ways to prove it.

I would start by noting that ##\cos (y)=\frac{e^{iy}+e^{-iy}}{2}##.

But show us how you would try to find the answer, please.
Remember that the real question is not to find the integral of ##\cos(x²)\cos(\omega x)##, but to find the Fourier transform of ##\cos(ax²)##. You could at least start by defining that Fourier transform in the "relevant equations" part of the template.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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