How to figure out the pressure when you pick up a cup upside down in water

In summary: He then pulled the tubing out and the tanks were filled with room-temperature water and the fish were happy :)In summary, this technique creates a vacuum at the top of a cup so that fish can swim up and down.
  • #1
JayRad
3
0
Pressure of water in upside down cup

We all played with a cup in a body of water, you know when you put it in water, turn it upside down and lift above the water level and the cup holds the water in, until you get above the water surface... So say you did that in a fish tank, could the fish swim up the cup, if you held it still, or is there too much pressure, and how would you measure that pressure? Please help I have no idea how to figure this out.
 
Last edited:
Physics news on Phys.org
  • #2
The pressure in the top of the cup is actually lower than atmospheric pressure. At the bottom of the cup, the pressure would be equal to atmospheric pressure (assuming the top of the cup is on the surface of the water). A fish should be able to swim into the cup with no problems.

The pressure at the top of the cup can be calculated by
[itex]\displaystyle P=101 kPA - \rho g h[/itex]
h is the height of the cup, 101 kPA is atmospheric pressure, and ρ is the density of water (1000 kg/m3). g, of course, is the gravitational acceleration on Earth's surface.
 
  • #3
I can't beat that reply but perhaps worth adding that the equation implies a maximium height before a vacuum forms at the top. The fish might have a problem approaching that limit that as there might be no disolved oxygen in the water?

It might be fun building an aquarium with an arch shaped tube that would allow the fish to travel up one side and back down the other.
 
  • #4
That aquarium idea does sound quite interesting.

I wonder though, with the water column (tube-arch) constantly drawing a negative (gauge) pressure, would it do as you said & cause the dissolved oxygen in the water to come out here?

That would cause an air bubble to form, slowly displacing the water in the arch, while also de-oxygenating the water.

If so, you'd need a good bubbler to keep up (keep the fish happy), as well as a way of periodically removing the trapped air (syringe & tubing).

Might want to do a simple test setup first, as a proof of concept.
 
  • #5
potatoecannon said:
That aquarium idea does sound quite interesting.
I wonder though, with the water column (tube-arch) constantly drawing a negative (gauge) pressure, would it do as you said & cause the dissolved oxygen in the water to come out here?
That would cause an air bubble to form, slowly displacing the water in the arch, while also de-oxygenating the water.
If so, you'd need a good bubbler to keep up (keep the fish happy), as well as a way of periodically removing the trapped air (syringe & tubing).
Might want to do a simple test setup first, as a proof of concept.

At room temperature, the vapor pressure of water is about 2 kPA. Doing a quick calculation, this means that in order to form vapor in the tube, the tube would need to be about 10.1 meters high; so unless you plan on having an extraordinarily high tube for the fish to swim through, you won't need to worry about forming vapor at the top.

This is the same reason I neglected to mention the maximum height for the equation I posted above. I figured the cup isn't going to be anywhere near 10 meters tall, which is when the pressure at the top starts to approach 0.
 
  • #6
I believe dissolved oxygen works slightly differently than the vapour partial pressure.

While I agree (& thank you for looking up the value) that you wouldn't be forming a large vapour bubble (essentially room temperature steam) for a short tube, I still think an air bubble may form (albiet slowly).

With a bubbler constantly trying to add air to the water (keeping it at the saturation point for room temperature/pressure), a low-pressure area would seem to invite rejecting disolved gas (like coming up from a dive).

If I'm completely off base with the above, I'd still say fish breath could collect there over time, so design for maintenance :)
 
  • #7
Yes, you can build this. My brother did it with his fish tanks, forming an arc that reached from one tank to the other by sticki ng up out of the water and over the edge of the tank at one end, and then went across the small space (about a foot, I think) between the two tanks, and down into the second.

After fabrication, he placed the two ends of the device into the two fish tanks, which he had filled much closer to their tops than normal. He then took some clear palstic tubing and slid it down into the water and up into the pipe. Once the end of the tube was in place, he put the other end in his mouth and satrted sucking the air out. Water rose up into the pipe from both ends as the air came out. He had to stop pretty soon, as the water levels in the tanks were getting closde to the ends of the pipe, so the tank needed re-filling.

After repeating this process several times, and I almost entirely filled with water. After that, he made sure that the input and output from the filter work in opposite tanks, to ensure that water was flowing through the pipe. The fish would swim through it, but only reluctantly. We always wondered if it was because of some pressure difference, but thought it was probably because of the exposed feeling.
 

1. How does picking up a cup upside down in water affect the pressure?

When you pick up a cup upside down in water, the pressure inside the cup decreases. This is because the weight of the water above the cup is no longer pushing down on it, causing a decrease in the overall pressure inside the cup.

2. How do you calculate the pressure when picking up a cup upside down in water?

The pressure when picking up a cup upside down in water can be calculated using the equation P = ρgh, where P is the pressure, ρ is the density of the water, g is the acceleration due to gravity, and h is the height of the water above the cup.

3. Does the size or shape of the cup affect the pressure when picking it up upside down in water?

The size and shape of the cup do not directly affect the pressure when picking it up upside down in water. However, they can indirectly affect it by changing the amount of water inside the cup and the distance between the cup and the surface of the water.

4. Can the pressure be negative when picking up a cup upside down in water?

Yes, the pressure can be negative when picking up a cup upside down in water. This occurs when the weight of the water above the cup is less than the weight of the cup, resulting in a negative value for pressure.

5. How does the depth of the water affect the pressure when picking up a cup upside down?

The depth of the water directly affects the pressure when picking up a cup upside down. The deeper the cup is submerged, the greater the weight of the water above it, resulting in an increase in pressure. This also means that the pressure will decrease as the cup is lifted closer to the surface of the water.

Similar threads

  • Mechanics
Replies
9
Views
2K
Replies
5
Views
2K
Replies
9
Views
2K
Replies
3
Views
1K
Replies
2
Views
2K
Replies
17
Views
2K
Replies
14
Views
2K
Replies
32
Views
7K
Replies
2
Views
2K
Back
Top